HW: Do all questions on side 2 of worksheet.
Lesson Review: Again, decide on which inverse to use for the first step: additive or multiplicative.
Example 1: 3x + 4 = 10 -----use the additive inverse of +4
- 4 = - 4
then continue 3x = 6----------use the multiplicative inverse by dividing by 3
Solution x = 2
Practive Exercises:
http://www.regentsprep.org/Regents/math/ALGEBRA/AE2/PTransSolvEq.htm
Answers to Homeowrk:
side one w/ work
2) 4(1) + 4(9x) = 4 + 36x 4) 2(9m)+ 2(10) = 18m + 20 6)
8(-b) - 4(8) = -8b - 32 8) -6(x) + -6(4) = -6x - 24 10) (-4)(-6p) + (-4)(7) = 24p -28 12) 5(x) + 5(9) = 5x + 45 14) -6(7) + -6(x) = -42 -6x 16) -5(10x) + -5(1) = -50x - 5 18) -8(1) + -8(-5x) = -8 + 40x 20) -5(7a) + -5(-6)= -35a + 30 22) 4(3r) - 4(8) = 12r - 32 24) -10(1) + -10(9x) = -10 -90x\
side two w/o work2) 12r - 20 4) -14x6) 4x + 11 8) 11v 10) 6p 12) -6n - 5 14) 1 + 9n 16) 3n 18) -k 20) -4n22) 2n + 18 24) 19 - 45n 26) -21 + 4m 28) -8n + 23 30) -71n - 29
Tuesday, September 16, 2008
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